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Listen : In qo: (a) x=45° [alternate interior angle]
(b) x=70° [corresponding angles]
(c) let the triangle be ∆ABC
:>A+B+C=180°
:>45°+B+60°=180°
:>B=180°-105°
:>B=75°
Triangle was stand on a straight line .
It means the straight line was 180°.
So,= x+B=180°
=x+75°=180°
=x=180°-75°
x=105° answer
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