Math, asked by arsh1138013973, 1 year ago

solve (1+root3)-(4+root3)​

Answers

Answered by AbhijithPrakash
2

Answer:

\left(1+\sqrt{3}\right)-\left(4+\sqrt{3}\right)=-3

Step-by-step explanation:

\left(1+\sqrt{3}\right)-\left(4+\sqrt{3}\right)

\gray{\mathrm{Remove\:parentheses}:\quad \left(a\right)=a}

=1+\sqrt{3}-\left(4+\sqrt{3}\right)

\black{-\left(4+\sqrt{3}\right):}

-\left(4+\sqrt{3}\right)

\gray{\mathrm{Distribute\:parentheses}}

=-\left(4\right)-\left(\sqrt{3}\right)

\gray{\mathrm{Apply\:minus-plus\:rules}}

\gray{+\left(-a\right)=-a}

=-4-\sqrt{3}

=1+\sqrt{3}-4-\sqrt{3}

\black{\mathrm{Simplify}\:1+\sqrt{3}-4-\sqrt{3}:}

1+\sqrt{3}-4-\sqrt{3}

\gray{\mathrm{Add\:similar\:elements:}\:\sqrt{3}-\sqrt{3}=0}

=1-4

\gray{\mathrm{Subtract\:the\:numbers:}\:1-4=-3}

=-3

Answered by adarshpal555
1

Answer:

Step-by-step explanation:

Here is the answer:

(1+√3)-(4+√3)

=1+√3-4-√3 ( the minus converts

plus to minus after

opening of bracket)

=1-4 +√3-√3( Rearranging)

=-3+0

= -3

This is the answer

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