Math, asked by misty73, 1 year ago

solve 1 + secA upon sec A is equals to sin square A

Answers

Answered by ayeza3
0
1+sec A=1secAI think it will help you
Answered by sushmitapant9
0

(1+secA)/secA=sin^2 (A)

1/secA +secA/secA =sin^2 (A)

cosA+1=sin^2 (A)

cosA+1-sin^2 (A)=0

cosA+cos^2 (A)=0

cosA (1+cosA)=0



cosA=0

cosA=pi/2

A=2npi+pi/2

A=2npi-pi/2npi


OR


1+cosA=0

cosA= -1

cos A=pi

A=2npi+pi

A=2npi-pi




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