Question

solve:- (1-tanΘ) (1+sin2Θ)= (1+tanΘ​

Answer 1

Step-by-step explanation:

Solution:

(1−tanθ) (1+sin2θ)=1+tanθ

−tanθ.sin2θ−tanθ+sin2θ=tanθ

− (-sinΘ/cosΘ)   ×2sinθcosθ+2sinθcosθ=2tanθ

2sinθcosθ−2sin²θ=2sinθ/cosθ

sinθ(cos²θ−sinθcosθ)=0

sinθcosθ(cosθ−sinθ)=0

sinθ=0

θ=nπ  n = 0,1,2,3,4........

cosθ=0 and (cosθ−sinθ)=0 will not satisfy  above equation.

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Answer 2

Step-by-step explanation:

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