Math, asked by gfgfggfgfgfgf, 8 months ago

solve: 1/(x-1)(x-2) + 1/(x-2)(x-3) = 2/3

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Answered by Anonymous
0

Answer:

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Answered by rumig0720
1

 \frac{1}{(x - 1)(x - 2)}  +  \frac{1}{(x - 2)(x - 3)}  =  \frac{2}{3}  \\  =  \frac{(x - 3) + (x - 1)}{(x - 1)(x - 2)(x - 3)}  = \frac{2}{3}  \\  =  \frac{2x - 4}{(x - 1)(x - 2)(x - 3)}  =  \frac{2}{3}  \\  = \frac{2x - 4}{(x - 1)(x - 2)(x - 3)} \times  \frac{3}{2}  = 0 \\  =  \frac{3(2x - 4)}{2(x - 1)(x - 2)(x - 3)} = 0 \\  = 3(2x - 4) = 0 \\  = 2x - 4 = 0  \\  = 2x = 4 \\  = x =  \frac{4}{2}  \\ x = 2

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