Question

solve : 1/x - 1/(x-2) = 3 ​

Answer 1

Answer:

2/3 and 1

Step-by-step explanation:

$\frac{1}{x} -\frac{1}{x-2}$ = 3

$\frac{x-2-x}{x^{2}-2x }$=3

$\frac{-2}{x^{2}-2x }$=3

-2=3x²-6x

3x²-6x+2=0

3x²-3x-2x+2=0

3x(x-1)-2(x-1)=0

(3x-2)(x-1)0

x=+2/3  x=+1

Answer 2

$\frac{1}{x} -\frac{1}{x-2} =3\\\\\frac{x-2-x}{x(x-2)} =3$

$\frac{-2}{x^{2}-2x } =3$

$-2=3x^2-6x\\3x^2-6x+2=0\\Now,\\x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

b=-6

a=3

c=2

Put the values and at last you will get:

1+(1/√3)    or    1-(1/√3)