Question

solve 1/x-1/x+5=1/360(x is ≠0​

Answer 1

hope it's helpful... .....

Answer 2

$Given \: \frac{1}{x} - \frac{1}{x+5} = \frac{1}{360}$

$\implies \frac{x+5-x}{x(x+5)} = \frac{1}{360}$

$\implies \frac{5}{x^{2}+5x} = \frac{1}{360}$

$\implies 5\times 360 = x^{2} + 5x$

$\implies x^{2} + 5x = 1800$

$\implies x^{2} + 5x - 1800=0$

/* Splitting the middle term, we get */

$\implies x^{2} + 45x-40x - 45 \times 40 = 0$

$\implies x(x+45) - 40(x+45) =0$

$\implies (x+45)(x-40) = 0$

$\implies x+45 = 0 \:Or \: x-40= 0$

$\implies x = - 45 \: Or \:x = 40$

Therefore.,

$\green { -45 \:or \: 40 \: are \: roots \:of }\\\green { given \: equation }$

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