Math, asked by itzvrushank, 1 month ago

solve [1/x + 1/y = 1/12] and [1/y + 1/2x = 1/15] by any method.​

Answers

Answered by bsnlazq123
1

Step-by-step explanation:

On putting

x

1

=X and

y

1

=Y in given equations, we get

3

X

+

5

Y

=

15

1

⇒5X+3Y=1 ...(i)

2

X

+

3

Y

=

12

1

⇒6X+4Y=1 ...(ii)

On multiplying (i) by 6 and (ii) by 5, we get

30X+18Y=6

3

0X

+

20Y=

5

−2Y=1

∴Y=−

2

1

On putting Y=−

2

1

in (i), we get

5X+3×−

2

1

=1⇒5X=

2

5

⇒X=

2

1

∴x=

X

1

=2,y=

Y

1

=−2

Answered by jacobjeso77
0

Answer:

On putting

x

1

=X and

y

1

=Y in given equations, we get

3

X

+

5

Y

=

15

1

⇒5X+3Y=1 ...(i)

2

X

+

3

Y

=

12

1

⇒6X+4Y=1 ...(ii)

On multiplying (i) by 6 and (ii) by 5, we get

30X+18Y=6

3

0X

+

20Y=

5

−2Y=1

∴Y=−

2

1

On putting Y=−

2

1

in (i), we get

5X+3×−

2

1

=1⇒5X=

2

5

⇒X=

2

1

∴x=

X

1

=2,y=

Y

1

=−2

Step-by-step explanation:

On putting

x

1

=X and

y

1

=Y in given equations, we get

3

X

+

5

Y

=

15

1

⇒5X+3Y=1 ...(i)

2

X

+

3

Y

=

12

1

⇒6X+4Y=1 ...(ii)

On multiplying (i) by 6 and (ii) by 5, we get

30X+18Y=6

3

0X

+

20Y=

5

−2Y=1

∴Y=−

2

1

On putting Y=−

2

1

in (i), we get

5X+3×−

2

1

=1⇒5X=

2

5

⇒X=

2

1

∴x=

X

1

=2,y=

Y

1

=−2

ok

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