Question

solve:1/x^2+1/y^2=41,1/x+1/y=9​

Answer 1

Answer:

1/x+1/y =9

Squaring on both sides

1x^2+1/y^2 +2/xy =81

Now subtraction given equipment with above equation

2/xy= 81-41

1/xy =40/2

1/xy= 20

1/x =20y

So

20y +1/y=9

20y^2 +1=9y

20y^2-9y+1=0

20y^2-5y-4y+1=0

5y ( 4y-1)-1(4y-1)=0

(4y-1)(5y-1) =0

4y=1. 5y=1

Y=1/4. Y=1/5

X=1/5. X=1/4

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Step-by-step explanation: