Question

solve.(1+x^2)dy = (4x^2-2xy)dx​

Answer 1

Answer: (1+x^2)dy/dx+2xy-4x^2=0

dy/dx+2xy/1+x^2=4x^2/1+x^2

where,y(IF)= integration of Q IF dx+c

y(1+x^2)=integration of 4x^2/1+x^2 (1+x^2)dx+c

y(1+x^2)=4 integration of x^2dx+c=4x^3/3+c

where, y=0,x=0

0(1+0)=4(0/3)+c=c=0

y(1+x^2)=4x^3/3