Question

solve :-
1-(x-2) -{(x-3) - (x-1)} = 0​

Answer 1

Answer:

$1 - (x - 2) - ((x - 3) - (x - 1)) = 0 \\ 1 - x + 2 - (x - 3 - x + 1) = 0 \\ 1 - x + 2 - x + 3 + x - 1 = 0 \\ 1 - 2x + x + 2 + 3 - 1 = 0 \\ 5 - x = 0 \\ 5 = x$

Answer 2

Step-by-step explanation:

1-(x-2)-{(x-3)-(x-1)} =0

1-(x-2)-{x-3-x+1}=0

1-(x-2)-{-2}=0

1-(x-2)+2= 0

1-x+2+2= 0

5-x= 0

x= 5-0

x= 5