Question

solve 1-(x-2)-(x-3)-(x-1)=0

Answer 1

Answer:

answer is 7/3

Step-by-step explanation:

answer is here....

Answer 2

Answer:

Required value of x is $2 \frac{1}{3}$

Step-by-step explanation:

Given,

$1 - (x - 2) - (x - 3) - (x - 1) = 0$

Here we want to find value of x.

First we are removing first bracket.

$1 - x + 2 - x + 3 - x + 1 = 0 \\ - 3x + 7 = 0 \\ - 3x = - 7 \\ x = \frac{ - 7}{ - 3} \\ x = \frac{7}{3} \\ x = 2 \frac{1}{3}$

This is a problem of Algebra.

Some important formulas of Algebra,

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)