Question

solve : 1-(x-2)- [(x-3)-(x-2)]=2x

Answer 1

hey mate

here goes ur answer

$1 - (x - 2) - ((x - 3) - (x - 2)) = 2x \\ 1 - (x - 2) - (x - 3 - x + 2) = 2x \\ 1 - x + 2 - ( - 1) = 2x \\ 1 - x + 2 + 1 = 2x \\ 4 - x = 2x \\ 4 = 3x \\ x = \frac{4}{3}$

hope it helps u....

Answer 2

The correct answer is "x = 4/3".

Step-by-step explanation:

$The \ given \ expression \ is:\\\\1-(x-2)-[(x-3)-(x-2)]=2x\\\\On \ solving \ brackets,we \ get\\\\1-(x-2)-[x-3-x+2]=2x\\\\1-x+2-[-1]=2x\\\\1-x+2+1=2x\\\\-x+4=2x\\\\On \ adding \ "x" \ both \ sides,we \ get\\\\-x+4+x=2x+x\\\\4=3x\\\\x=\frac{4}{3}$

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