SOLVE:-
1) (x+5) (x+4)
2) 100a²-121b²
3) (2p+q)²-(p-q)²
4) xy+2x+y+2
5) ab-5b+a-5
Answers
Answered by
2
Answer
1). (x+5)(x+4)
= x(x+4)+5(x+4)
=x^2+4x + 5x + 20
=x^2+9x + 20
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Answered by
1
Hey Mate!!
1) (x+5) (x+4) ;
x(x+4) + 5 (x+4) [ After Distribution]
2) 100a^2 - 121b^2 ;
We know that a^2 - b^2 = (a+b) (a-b)
a= 100a and b= 121b
So, 100a²-121b² = (100a+121b) ( 100a-121b )
3) (2p+q)²-(p-q)² ;
Same as before. a^2 - b^2 = (a+b (a-b)
a=2p+q and b= p-q
(2p+q)²-(p-q)² = [(2p+q) +(p-q)] [( 2p+q)-(p-q)]
4) xy+2x+y+2 ;
xy+2x+y+2
=(y+2)(x+1)
5) ab-5b+a-5 ;
ab+a−5b−5
=(b+1)(a−5)
Hope this helps you!!
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