solve : 1/(x1)(x-2)+1/(x-2)(x-3)=2/3, x is not =1, 2, 3.
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1/(x-1)(x-2)+1/(x-2)(x-3)=2/3
1/(x-2) [1/(x-1) +1/(x-3)]=2/3
(2x-4)/(x-1) (x-2) (x-3) =2/3
2(x-1) /(x-1) (x-2) (x-3) =2/3
3=(x-2) (x-3)
x²-5x+6=3
x²-5x+3=0
x=(5±√13) /2
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