Math, asked by blessy4116, 10 months ago

solve : 1/(x1)(x-2)+1/(x-2)(x-3)=2/3, x is not =1, 2, 3.​

Answers

Answered by pal69
1

Answer:

1/(x-1)(x-2)+1/(x-2)(x-3)=2/3

1/(x-2) [1/(x-1) +1/(x-3)]=2/3

(2x-4)/(x-1) (x-2) (x-3) =2/3

2(x-1) /(x-1) (x-2) (x-3) =2/3

3=(x-2) (x-3)

x²-5x+6=3

x²-5x+3=0

x=(5±√13) /2

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