Question

Solve.
10
) Find the distance between the points P(-5, -4) and Q(3,-7).​

Answer 1

Step-by-step explanation:

distance between two points is

D = 17 units

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Answer 2

Answer :-

• Here,the distance between the points are P(-5,-4) and Q(3,-7).Let us apply the formula distance between two points.

$\\ \underline{\bf{\red{\bigstar}\;Formula:-}}\\ \\ \\ \blue{\bigstar}\;\underline{\boxed{ \;\;\mathsf{PQ=\sqrt{\big(x_2-x_1\big)^{2}+\big(y_2-y_1\big)^2}}\;}}\;$

Where,

• x1 = -5, y1 = -4
• x2 = 3,y2 = -7

Then,

Putting the values,

$\\ :\implies\sf{PQ=\sqrt{\big(3-(-5)\big)^2+\big(-7-(-4)\big)^2}}\\ \\:\implies\sf{PQ=\sqrt{\big(3+5\big)^2+\big(-7+4\big)^2}}\\ \\ :\implies\sf{PQ=\sqrt{\big(8\big)^2+\big(-3\big)^2}}\\ \\ :\implies\sf{PQ=\sqrt{64+9}}\\ \\ :\implies\sf{PQ=\sqrt{73}}\\ \\ :\implies\sf{PQ=8.54}$

• ∴ Hence,the distance between two points is 8.54 units.