Solve 10 sum based on Bodmas
Answers
Example 1: Solve: 10 + 10 × 10 ÷ 10.
Sol: Applying BODMAS rule: 10 + 10 × 10 × (1/10) ⇒ 10 +10 = 20
Example 2: 8 + 8 of 8 ÷ 8 - 34/5
Sol: 8 + 64 ÷ 8 - (34/5) (Note: ‘of’ must be solved before ‘÷’)
= 8 + 8 - (34/5) ⇒ 16 - (34/5) = 46/5
Example 3: Simplify the expression: 18 – [6 – {4 – (8 – 6 + 3 )}]
Sol: This is an example where brackets are given. Brackets are solved after Bar. The order of Solving the brackets is (), {} and [] respectively. So, the solution of above examples is as follows.
= 18 – [6 - {4 – (8 – 9)}] ⇒ 18 – [6 – {4 – (- 1)}]
= 18 – [6 - {4 + 1}] ⇒ 18 – [ 6 – 5] 18 – [ 1] = 18 – 1 = 17
Example 4: Solve
20+20×20÷20/20×20÷+20
Sol: 20+20×20÷20/20×20÷+20 = 20+20×20×(1/2)/20×20×(1/20)+20
=20+20/20+20=40/40=1
Example 7 Simplify: 8÷8 of 8+8/8÷8×8+8
Sol: 8÷8 of 8+8/8÷8×8+8 ⇒ 8÷64+8/8×(1/8)×8+8
8×(1/64)+8/8+8 = (1/8)+8/16 ⇒ 65/8 × 1/16 = 65/128
Example 8: 3√125-√? = 3
>Sol: 5-√x =3
5 – 3 = √x
√x = 2 ⇒ x = 4.
Example 9: Solve; 30% of 300 + x % of 50 = 60% of 400.
Sol: 30% of 300 + x% of 50 = 60% of 400.
90 + (x/2) = 240
x/2 = 240 – 90
x/2 =150 ⇒ x = 150 2 =300
Example 10 : Solve; 6162 + ? + 3330 = 2545.
Sol: 6162 + x + 3330 = 2545
x = 2545 – 6162 – 3330 = 2545 – 9492 = - 6947.
With a simple sum that only has two numbers and one single operation, or sign, it’s easy to see how to calculate the answer. Either you add, subtract, multiply, or divide.
But what about when there are several numbers, and different operations? Maybe you need to divide and multiply, or add and divide. What do you do then?
Fortunately, mathematics is a logic-based discipline. As so often, there are some simple rules to follow that help you work out the order in which to do the sum.