solve 10 (y+1) + 5 (2y + 4) =2 (6-y)
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Answered by
0
10(y+1)+5(2y+4)=2(6-y)
10y+10+10y+20=12-2y
10y+10y+2y+10+20-12=0
22y+18=0
22y=-18
y=-18/22
i.e y =-9/11
10y+10+10y+20=12-2y
10y+10y+2y+10+20-12=0
22y+18=0
22y=-18
y=-18/22
i.e y =-9/11
Answered by
1
10 (y+1) + 5 (2y + 4)= 2 (6-y)
10y+10 + 10y + 20= 12- 2y
20y + 30 = 12- 2y
20y + 2y= -30+12
22y = -18
y=-18/22
10y+10 + 10y + 20= 12- 2y
20y + 30 = 12- 2y
20y + 2y= -30+12
22y = -18
y=-18/22
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