Solve 103^2 using identities
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(103)^2=
(100+3)^2=
(a+b)^2=a^2+2ab+b^2
=(100^2)+2*100*3+(3^2)=
10000+600+9=10609
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(100+3)^2=
(a+b)^2=a^2+2ab+b^2
=(100^2)+2*100*3+(3^2)=
10000+600+9=10609
hope you like the answer...
plz mark as brainliest...
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