solve 10sin⁴x + 15cos⁴x = 6 find the value of 27 cosec^6x + 8sec^6x ??
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10sin⁴x + 15cos⁴x = 6
10sin⁴x+15cos⁴x = 6(sin²x+cos²x)
10tan⁴x + 15=6(tan²x+1)²
so by dividing by cos⁴x
(2tan²x -3)² =0
tan²x =3/2
27cosec^6x + 8se'^6x
27(1+cost²x)³+8(1+tan²x)
27(1+2/3)³+8(1+3/2)²
27× 125/27 +8*(125/8)
=250
how it helps you
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