Question

solve 10sin⁴x + 15cos⁴x = 6 find the value of 27 cosec^6x + 8sec^6x ??​

Answer 1

10sin⁴x + 15cos⁴x = 6

10sin⁴x+15cos⁴x = 6(sin²x+cos²x)

10tan⁴x + 15=6(tan²x+1)²

so by dividing by cos⁴x

(2tan²x -3)² =0

tan²x =3/2

27cosec^6x + 8se'^6x

27(1+cost²x)³+8(1+tan²x)

27(1+2/3)³+8(1+3/2)²

27× 125/27 +8*(125/8)

=250

how it helps you