Question

solve 10sin⁴x + 15cos⁴x = 6 find the value of 27 cosec^6x + 8sec^6x ??

Answer 1

Hey mate,

➡10sin⁴x + 15cos⁴x = 6

➡10sin⁴x+15cos⁴x = 6(sin²x+cos²x)

➡10tan⁴x + 15=6(tan²x+1)²

so by dividing by cos⁴x

➡(2tan²x -3)² =0

➡tan²x =3/2

➡27cosec^6x + 8se'^6x

➡27(1+cost²x)³+8(1+tan²x)


➡27(1+2/3)³+8(1+3/2)²

➡27× 125/27 +8*(125/8)

=250

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Answer 2

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