Question

solve 10th question ..............
with proper solution

Answer 1

$\textbf { Hey Mate}$

$\textbf { your answer is -- }$



Given, x = 2+√3

so, 1/x = 1/(2+√3) = 2-√3

Now,

$x + \frac{1}{x} = 2 + \sqrt{3} + 2 - \sqrt{3} = 4$



Therefore,

${( \sqrt{x} + \frac{1}{ \sqrt{x} }) }^{2} = x + \frac{1}{x} + 2 \\ \\ = > {( \sqrt{x} + \frac{1}{ \sqrt{x} } )}^{2} = 4 + 2 = 6 \\ \\ = > \sqrt{x} + \frac{1}{x} = \sqrt{6}$


$\textbf { Hope it help you }$