Question

Solve 10y (6y + 21) ÷ 5(2y+7)​

Answer 1

$\tt\red{Question}\implies 10y(6y+21) \div 5(2y+7)$

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$\tt\red{To \: Find}\implies$ Division Calculation/Equation.

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$\purple{━━━━━━━━━━━━━━━━━━━━━━━━━━}$

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$\implies\frac{60y^{2}+210y}{5}\left(2y+7\right) \\ \\ \\ \implies\frac{\left(60y^{2}+210y\right)\left(2y+7\right)}{5} \\ \\ \\ \implies \frac{120y^{3}+420y^{2}+420y^{2}+1470y}{5} \\ \\ \\ \implies \frac{120y^{3}+840y^{2}+1470y}{5} \\ \\ \\ \implies { \underbrace{ \underline{ \overbrace\red{ \boxed{\mathfrak{6y\left(2y+7\right)^{2}}}}}}}$

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$\purple{━━━━━━━━━━━━━━━━━━━━━━━━━━}$

⠀⠀⠀⠀⠀⠀⠀⠀★Regards★

Answer 2

Answer :

$\large \implies \tt 6y$

Solution :

To solve :

$\tt \large \: \: \: \: \implies \large \frac{10y (6y + 21)}{5(2y+7)}$

Let's solve ,

$\sf \: \: \implies \frac{10y (6y + 21)}{5(2y+7)}$

$\\ ::\implies \sf \frac{(2y\times \cancel{5}) (6y + 21)}{ \cancel{5} ((2y+7)}$

$\\ \sf ::\implies \frac{2y (6y + 21)}{(2y+7)}$

• Opening brackets by multiplying inside
$\sf ::\implies \frac{ 12y^2 + 42y}{2y+7}$

• Taking 6y common from numerator.
$\sf ::\implies \frac{6y \cancel{(2y+7)}}{\cancel{(2y+7)}}$

$\\ ::\implies \sf \boxed{\sf \pink \sf{6y}}$

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