solve 11 question from the data
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(11).
Given : P(m + n,2) = 56 and P(m - n,2) = 30.
(i) Let m + n = a
= > a!/(a - 2)! = 56
= > a(a - 1)(a - 2)!/(a - 2)! = 56
= > a(a - 1) = 56
= > a(a - 1) = 8 * 7
= > a(a - 1) = 8 * (8 - 1)
= > a = 8.
Then, m + n = 8. -------- (1)
Now,
(ii) Let m - n = b
= > b!/(b - 2)! = 30
= > b(b - 1)(b - 2)!/(b - 2)! = 30
= > b(b - 1) = 30
= > b(b - 1) = 6 * (6 - 1)
= > b = 6
Then, m - n = 6. ------ (2)
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On solving (1) & (2), we get
= > m + n = 8
= > m - n = 6
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2m = 14
m = 7.
Substitute m = 7 in (1), we get
= > m + n = 8
= > 7 + n = 8
= > n = 8 - 7
= > n = 1.
Therefore, the value of m = 7, n = 1.
Hope this helps!
siddhartharao77:
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hope it helps you.........
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