Question

Solve 11a² + 2a – 3 = 0 by using quadratic formula.​

Answer 1

a=11 b=2 c=–3

D = b² – 4ac

D= (2)² – 4(11)(–3)

D = 4 + 132

D= 136

X= –3

X= 0.5

Answer 2

Step-by-step explanation:

b²-4ac= 2² - 4x11x(-3)

= 4+132

=136

$a = \frac{- {b}^{2} + \sqrt{ {b}^{2} - 4ac} }{2a} \\ = \frac{ - 4 + \sqrt{136} }{22} \\ = \frac{ - 4 + 2 \sqrt{34} }{22} \\ = \frac{ - 2 + \sqrt{34} }{11} \\ or \\ a = \frac{- {b}^{2} - \sqrt{ {b}^{2} - 4ac} }{2a} \\ = \frac{ - 4 - \sqrt{136} }{22} \\ = \frac{ - 4 - 2 \sqrt{34} }{22} \\ = \frac{ - 2 - \sqrt{34} }{11}$