Question

solve 11b - 7a=1 and 9b -4a =1 by eliminating method​

Answer 1

11b-7a=1×9

Therefore, 99b-63a=9

Similarly 9b-4a=1×11

Therefore,99b-44a=11

Now,

99b-63a=9

99b-44a=11

(After changing the negatives to postives and vice versa)

The sum becomes

99b-63a=9

-99b +44a =11

Therefore, - 19a=-2

.

. . a=2/19

Putting the value in any equation

9b-4(2/19)=1

9b - 8/19=1

Therefore, b=8/19(9)