Question

Solve 11x - 5y = -61 and 3x - 20y = 2 by elimination method

Answer 1

Given equations

$11x-5y=-61--(1)\\3x-20y = 2--(2)$

Multiply the first equation with 3

and the second equation with 11, we get,

$33x-15y=-183\\\underline{33x-220y=22}\\\underline{\underline{205y = -205}}$

$\implies y = \dfrac{-205}{205}$

$\implies y = -1$

Substituting the value of y in the second equation, we get,

$3x-20(-1) = 2$

$\implies 3x+20=2$

$\implies 3x = -18$

$\implies x = \dfrac{-18}{3}$

$\implies x = -6$

$\boxed{\boxed{\bold{Therefore, \ the \ values \ of \ x \ and \y \ are \ -6 \ and \ -1 \ respectively}}}}}}$