Question

solve 12÷by 100 _ 19​

Answer 1

Answer:

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Answer 2

Answer:

Let n be the number of numbers in the sequence; so, in this case n=49.

The first and last number add to n+1, the second and second to last number add to n+1, the third and third to last add to n+1, and so on. There are n/2 sums adding to n+1 since each sum has two numbers. So, we have a total of n(n+1)/2.

What I mean is 1+49=2+48=3+47 and so on. (The 25 left over is like half a sum.)

So, we have 49/2 sums of 50 each and 50*49/2=1225.