Question

solve -12 upon 13 + -15 upon 13​

Answer 1

Answer:Consider a normal equation in #x# such as: #3x=6# To solve this equation you simply take the #3# in front of #x# and put it, dividing, below the #6# on the right side of the equal sign. #x=6/3=3^-1*6=2# at this point you can "read" the solution as: #x=2#. With a system of #n# equations in #n# unknowns you do basically the same, the only difference is that you have more than 1 unknown (and equation) that can …

Step-by-step explan

Answer 2

Answer:

A.T.Q

$= \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{ - 12}{13} + \frac{ - 15}{13} \\L.C.M \: of \: 13 and13 \: is13\\ = \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{ - 12 + ( - 15)}{13} \\ = \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{ - 12 - 15}{13} \\ = \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \huge \frac{27}{13}$

so, the required answer is →

27/13

Step-by-step explanation:

hope it's helpful,,,

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