Solve : 13) if cosec theta =√5...
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Answer:
If cosec theta= 13/5
as sin= 1/cosec= 5/13
cos = √1-sin^2 theta
= √1-(25/169
= √144/169= 12/13
tan = sin /cos= 5/13/(12/13)
= 5/12
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Answer :
If cosec theta = √5 and theta is less than 90°, the value of cot theta - cos theta will be 2(√5 - 1)
Theta is less than 90°
cosec theta=√5/1(h/p)
cot theta-cos theta
=(2/1-2/√5)
=(2√5-2/√5)
=so,2(√5-1)...
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