Solve
13+ ytanx = cos 3 x
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Answer:
Step-by-step explanation:
ANSWER
Given,
dx
dy
−ytanx=e
x
secx
It is a first-degree linear D.E of the form
dx
dy
+Py=Q
here P=−tanxQ=e
x
secx
I.F=e
∫pdx
=e
∫−tanxdx
=e
−log∣secx∣
=e
logcosx
=cosx
The solution is given by,
y×I.F=∫Q×I.Fdx+c
⇒y×cosx=∫e
x
secx×cosxdx+c
⇒ycosx=∫e
x
dx+c
⇒ycosx=e
x
+
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