Question

Solve 13(z-4)-3(z-9)-5(z+4)=0

Answer 1

13(z-4)-3(z-9)-5(z+4)=0
13z-52-3z+27-5z-20=0
13z-8z-52+27-20=0
5z-72+27=0
5z-45=0
5z=45
z=45÷5
z=9

Answer 2

The value of z in equation 13(z - 4) -3(z - 9) - 5(z + 4) = 0 is 9.

Concept used:

• Collect all the terms containing the variable on one side of the equation (LHS) and all constant terms (RHS) on the other side.
• Dividing both sides of the equation by the resulting coefficient of the variable.

Given :

The equation is

13(z - 4) -3(z - 9) - 5(z + 4) = 0

To find:

The value of z.

Solution:

Step 1: Simplifying the given equation by solving the brackets:

13(z - 4) -3(z - 9) - 5(z + 4) = 0

13z - 52 - 3z + 27- 5z - 20= 0

Step 2: Collecting terms containing Z on the LHS and constants on the RHS:

13z - 3z - 5z = - 27 + 20 + 52

13z - 8z = -7 + 52

5z = 45

z =$\frac{45}{5}$

z = 9

Hence, the value of z is 9.

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