solve ,..................
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Where,
l = lower limit of the modal class = 200
f0 = frequency of the class preceding the modal class = 18
f1 = frequency of the modal class = 27
f2 = frequency of the class succeeding the modal class = 20
c = size of class interval (the class intervals are same) = 100
∴ Substituting the values l = 200, f0 = 18, f1 = 27, f2 = 20 and c = 100 in the formula of mode. We get,
Mode= 200(27+18)/2×27-18-20 ×100
=200+225/4
=200+56.5
=256.25
Hope it helps you ❣️☑️
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