Question

Solve: 14 = 3y + x ; 20 = 2y -3x​

Answer 1

Answer:

x+3y=14. (1)

-3x+2y=20. (2)

multiply equation (1) by 3

3x+9y=42

-3x+2y=14

___________

11y=42+14

11y=56

y=56/11

x+3y=14

x=14-3(56/11)

x=14-168/11

x=154-168/11

x=14/11

Answer 2

Answer:

The value of x is $\frac{-32}{ 11}$ and  the value of y is $\frac{62}{ 11}$

Step-by-step explanation:

Explanation:

Given , 3y + x = 14 and

            2y - 3x = 20

To solve the given equations we use elimination method. It's the process in which removing one of the variables of the system of direct equations using the system of addition or deduction in combination with the multiplication or division of the portions of the variables.

Step 1:

Let  3y + x = 14 .........(i)

and let 2y - 3x = 20 ........(ii)

Multiply 3 in equation (i)  

3(3y  +  x ) = 3(14)

⇒ 9y +3x = 42    ......(iii)

Adding (ii) and (iii)

2y -3x  + 9 y + 3x = 42 + 20

⇒11y = 62

⇒ y = $\frac{62}{11}$  

Step 2:

put y = $\frac{62}{11}$ in any one of the given equation .

On putting  y = $\frac{62}{11}$  in equation  ( i ) we get ,

3y + x= 14

⇒3 ×  $\frac{62}{11}$  + x= 14

⇒$\frac{ 186 + 11x }{11}$ = 14

⇒186 + 11 x=14 × 11

⇒11x = 154 - 186 = -32

⇒ x = $\frac{-32}{ 11}$

Final answer:

Hence , the value of x is $\frac{-32}{ 11}$ and y is $\frac{62}{ 11}$

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