solve 14 and 15.............
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Answered by
3
Answer:
The answer for number 15 is 40°
Step-by-step explanation:
1- AB and AC are equal, therefore the triangle is an isosceles triangle.
2- In an isosceles triangle the two equal sides have the same equal angle, i.e <B= 50° therefore <C= 50°.
3- Every triangle has a total of 180°, i.e <A+<B+<C= 180°. We already know <B and <C so now we can find angle A.
<A+50+50=180
<A+100=180
<A=180-100
<A=80°
4- AD is median, that means angle A is divided into 2 equal parts. There <BAD=<A/2
<BAD=80/2
<BAD= 40°
Answered by
1
Answer:
14). <4=(160-3y)° ;<5=(3y+20)°
Step-by-step explanation:
GIVEN: <1=(2x+y)°,<2=(x+2y)°,<3=(3y+20)°
<3=<5=(3y+20)° [vertically opposite <s]
& <3+<4=180° [by linear pair]
→3y+20°+<4=180°
→<4=180°-3y-20°
→<4=160°-3y
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