solve 14 (i) question in full solution
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Hi ,
LHS = [ cos(90 - A ) sin( 90 - A ) ]/tan( 90 - A )
= [ SinA cosA ] / cotA
= ( SinA cosA ) / ( cosA/sinA )
= ( SinAcosA sinA ) / cosA
= Sin² A
= 1 - cos² A
= RHS
I hope this helps you.
:)
LHS = [ cos(90 - A ) sin( 90 - A ) ]/tan( 90 - A )
= [ SinA cosA ] / cotA
= ( SinA cosA ) / ( cosA/sinA )
= ( SinAcosA sinA ) / cosA
= Sin² A
= 1 - cos² A
= RHS
I hope this helps you.
:)
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