solve 14 question with steps full solution plz
Answers
Hope it will help you
So, to solve your problem, we have to apply the Pythagorean relation.
So let one of the perpendicular sides be x. Then the other is x+4, because it is given that it is greater than x by 4cm. Then your hypotenuse is x+4+4 = x+8, because the hypotenuse is 4 more than the x +4.
So we just apply the pythagorean relation to these values.
x^2 + (x+4)^2 = (x+8)^2
x^2 + x^2+8x+ 16 = x^2+16x+64
since x^2 is common to both sides, it cancels out.
x^2+8x+16 = 16x + 64
x^2+8x +16 - 8x-16 = 16x+64-8x-16
x^2 = 8x+48
Then we build up the quadratic equation by carrying the right hand side over to the left hand side.
x^2-8x-48 = 0
x^2 -12x+4x -48 = 0
x(x-12) +4(x-12) = 0
(x-12)(x+4) = 0
the one of (x-12) or (x+4) is forced to be 0. but if x+4 is 0, x would be -4, and it can not happen as x is a side length. So x-12 should be 0. then x is 12. so the other perpendicular side is 16cm.
Now, the area of a right triangle is half into the product of the 2 perpendicular sides.
= 12 * 16 /2
= 12*8
=96
So, YAYYY, we solved the problem!!!
If I helped ya, pleeeeeeeeeeeeeeeease mark me brainliest!!!