Question

solve;
15-(7-q)/6(q-2)+3=3/5​

Answer 1

q = 1.89

• An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation with one variable has the conventional form Ax + B = 0. In this case, the variables x and A are variables, while B is a constant.
• A linear equation is one that has a degree of 1 as its maximum value. No variable in a linear equation, thus, has an exponent ghan 1. A linear equation's graph will always be a straight line.
• Each term in a linear equation has an exponent of 1, and when this algebraic equation is graphed, it always produces a straight line. It is called a "linear equation" for this reason.

Given that,

$15 - \frac{7-q}{6(q-2)} + 3 =\frac{3}{5}$

Or, $15 - \frac{7-q}{6q-12} + 3 =\frac{3}{5}$

Or, $\frac{90q-180-7+q+18q-36}{6q-12}=\frac{3}{5}$

Or, $\frac{118q-223}{6q-12} =\frac{3}{5}$

Or,  590q - 1115 = 18q - 36

Or, 572q = 1079

Or, q = 1.89

Hence, q = 1.89

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