Question

solve: 15 y-2(4y-1)=2(3y -1)​

Answer 1

$\huge \mathfrak \green{Solution}$

:$\implies$ $\sf 15y-2(4y-1) = 2(3y-1)$

:$\implies$ $\sf 15y-8y+2 = 6y-2$

:$\implies$ $\sf 7y+2 = 6y-2$

:$\implies$ $\sf y = -4$

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hope it's fine ⭐⭐⭐

Answer 2

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

$\sf \longmapsto15y - 2(4y - 1) = 2(3y - 1)$

Concept : When - value multiply with -value it gets cancelled and resultant we obtain be a positive value.

[minus minus =plus (but sign of -)]

[plus minus =minus ]

$\sf \longmapsto15y - 8y + 2 = 6y - 2$

$\sf \longmapsto7y + 2 = 6y - 2$

Now,taking like terms together

$\sf \longmapsto7y - 6y = - 2 - 2$

$\sf \boxed{\bold{{y = - 4}}}$

Check

$\sf \longmapsto15( - 4) - 2(4( - 4) - 1) = 2(3( - 4) - 1)$

$\sf \longmapsto - 60 - 2( - 16 - 1) = 2( - 12 - 1)$

$\sf \longmapsto - 60 - 2( - 17) = 2( - 13)$

$\sf \longmapsto - 60 + 34 = - 26$

$\sf \longmapsto - 26 = - 26$