Question

solve 15x2-15=-16x using -b+-√b2-4ac/2a​

Answer 1

Answer:

Solving discriminant first: b^2 - 4ac( in eq. )

= > (  -  )^2 - 4(1)(-)

= > ()^2 + ()^2 - 2 + 4

= > ()^2 + ()^2 + 2

= > (  +  )^2

Now,

= > [ -(-) ]/2

= > [ -  +  +  +  ] / 2 or [ - +  -  -  ] / 2

= > 2/2 or - 2/2

= > root B or -  Root A

Hence, x = root B or - root a