Math, asked by saral419, 6 months ago

solve 15x²-28=x
with the process

#maths_class_10_questions​

Answers

Answered by Askme005
3

Answer:

X=

7/5 or

-4/3

Step-by-step explanation:

or, 15x²-x-28=0

or, 15x²-21x+20x-28=0

or, 3x(5x-7)+4(5x-7)=0

or, (5x-7)(3x+4)=0

Either,

5x-7=0

or, X=7/5

or, 3x+4=0

or, X=-4/3

Answered by nandu6022
2

Answer:

15x^2-28=x

making in standard form

15x^2-x-28=0

To solve means find the value of x,

Since it is in Quadratic form, we can use either splitting the middle term or quadratic formula..

Using splitting the middle term,

Product=-420

Sum=-1

15x^2+20x-21x-28(since the numbers product is -420 and sum is -1)

=5x(3x+4) -7(3x+4)

Taking common outside

(3x+4)(5x-7) =0

3x+4=0 Or 5x-7=0

x=-4/3 Or x=7/5

If it helped u.. pls mark it brainliest

Similar questions