Math, asked by yogesstha, 1 month ago

Solve 16^p - 5 × 4^(p+1) +64=0​

Answers

Answered by mailsuneet1234pca4l0
4

Answer:

16^p - 5×4^p × 4^1 +64=0

4^2p -20×4^p+64=0

let 4^p = y

y^2- 20y + 64=0

y^2-16y-4y+64=0

y(y-16) -4(y-16) =0

(y-16) (y-4) =0

y=16, 4

4^p=16, 4

4^p =4^2, 4^1

=p=2, 1

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