solve 16 with steps......
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Step 1 :
It is given that the line makes an angle of 30∘ with y - axis.
∴The angle made with x axis in the positive direction is 60∘
∴tan60∘=√3
Hence slope m=√3
It is given that it passes through the point (1, 2)
Step 2 :
Hence the equation of the line is
(y−2)=√3(x−1)
⇒y−2=-√3+√3x
i.e y−√3x−2+√3=0
Hence the equation of the required line is
y−√3x−2+√3=0.
hope it helps you
It is given that the line makes an angle of 30∘ with y - axis.
∴The angle made with x axis in the positive direction is 60∘
∴tan60∘=√3
Hence slope m=√3
It is given that it passes through the point (1, 2)
Step 2 :
Hence the equation of the line is
(y−2)=√3(x−1)
⇒y−2=-√3+√3x
i.e y−√3x−2+√3=0
Hence the equation of the required line is
y−√3x−2+√3=0.
hope it helps you
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