Math, asked by Triptidave5, 11 days ago

Solve: 16-x/3=15

Solve: -2x+3=7

Answers

Answered by Anonymous
17

\large\sf\underline{Question\:1\::}

  • \sf\:16-\frac{x}{3}=15

\large\sf\underline{Solution\::}

\sf\:16-\frac{x}{3}=15

  • LCM of 1 and 3

\sf\implies\:\frac{48-x}{3}=15

  • Transposing 3 to the other side

\sf\implies\:48-x=15 \times 3

\sf\implies\:48-x=45

\sf\implies\:-x=45 -48

\sf\implies\:-x= -3

\sf\implies\:\cancel{-}x= \cancel{-}3

\large{\mathfrak\red{\implies\:x\:=\:3}}

\large\sf\underline{Verifying\:my\:answer\::}

\sf\:16-\frac{x}{3}=15

  • Substituting the value of x as 3

\sf\:16-\frac{3}{3}=15

\sf\implies\:48-3=15 \times 3

\sf\implies\:45=45

\small\fbox\green{[\:Hence\:verified\:]}

\dag\:\underline{\sf Value\:of\:x\:=\:3.}{\sf{{\pink{★}}}}

________________________

\large\sf\underline{Question\:2\::}

  • \sf\:-2x+3=7

\large\sf\underline{Solution\::}

\sf\implies\:-2x+3=7

  • Transposing 3 to the other side

\sf\implies\:-2x=7-3

\sf\implies\:-2x=4

  • Transposing -2 to the other side

\sf\implies\:x=\frac{4}{-2}

\sf\implies\:x=\cancel{\frac{4}{-2}}

\large{\mathfrak\red{\implies\:x\:=\:-2}}

\large\sf\underline{Verifying\:my\:answer\::}

\sf\implies\:-2x+3=7

  • Substituting the value of x as -2

\sf\implies\:-2 (-2) +3=7

\sf\implies\:-2 \times -2 + 3=7

\sf\implies\:4 + 3=7

\sf\implies\:7=7

\small\fbox\green{[\:Hence\:verified\:]}

\dag\:\underline{\sf Value\:of\:x\:=\:-2.}{\sf{{\pink{★}}}}

‎ ________________________

!! Hope it helps !!

Answered by JahnaviS1577
15

ANSWER

{\mathsf{\frac{16-x}{3}=15}}

{\mathsf{\sf{ 16-x = 15 × 3}}}

{\sf{\mathsf{ 16-x = 45}}}

{\sf{\mathsf{ -x = 45-16}}}

{\sf{\mathsf{ -x = 29}}}

{\sf{\mathsf{ -x × (-1) = 29 × -(1)}}}

\bold{\sf{\underline{\mathsf{ x = -29}}}}

_________________________

{\mathsf{ -2x + 3 = 15}}

{\mathsf{ -2x = 15 - 3}}

{\mathsf{ -2x = 12}}

{\mathsf{ x ={\frac{12}{-2}}}}

\bold{\underline{\mathsf{ x = -6}}}

____________________________

Hope this helps ya! ♡

~Jahnavi♪♫

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