solve 16x^2 + 9 = 0
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Answer:
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
1
6
2
+
9
=
0
16x^{2}+9=0
16x2+9=0
=
1
6
a={\color{#c92786}{16}}
a=16
=
0
b={\color{#e8710a}{0}}
b=0
=
9
c={\color{#129eaf}{9}}
c=9
=
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0
±
0
2
−
4
⋅
1
6
⋅
9
√
2
⋅
1
6
Step-by-step explanation:
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