Math, asked by Anonymous, 1 day ago

Solve 17,18 & 19 fast!​

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Answers

Answered by sainlab1895
2

Answer:

your answe

may it help you

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Answered by tennetiraj86
6

Step-by-step explanation:

17.

Given that ab(a²+b²)

=> (ab×a²)+(ab×b²)

=> a³b+ab³

The product of ab(a²+b²) is a³b+ab³ --------(1)

Put a = 2 and b= 1/2 in (1) then

=> 2³(1/2)+2(1/2)³

=> (8/2)+2(1/8)

=> (8/2)+(2/8)

=> 4+(1/4)

=> (4×4+1)/4

=> (16+1)/4

=> 17/4

The value of the product is 17/4

18.

Given that s(s²-st)

=> (s×s²)-(s×st)

=> s³-s²t

The product of s(s²-st) is s³-s²t --------(1)

Put s = 2 and t = 3 in (1) then

=> 2³-2²(3)

=> 8-(4×3)

=> 8-12

=> -4

The value of the product is -4

19.

Given that -3y(xy+y²)

=> (-3y×xy)+(-3y×y²)

=> -3xy²-3y³

The product of -3y(xy+y²) is -3xy²-3y³ --------(1)

Put x = 4 and y = 5 in (1) then

=> -3(4)(5)²-3(5)³

=> -3(4)(25)-3(125)

=> -300-375

=> -675

The value of the product is -675

20.

Given that

a(b-c)+b(c-a)+c(a-b)

=> ab-ac+bc-ab+ac-ab

=> (ab-ab)+(bc-bc)+(ac-ac)

=> 0+0+0

=> 0

a(b-c)+b(c-a)+c(a-b) = 0

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