Solve 17,18 & 19 fast!
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Step-by-step explanation:
17.
Given that ab(a²+b²)
=> (ab×a²)+(ab×b²)
=> a³b+ab³
The product of ab(a²+b²) is a³b+ab³ --------(1)
Put a = 2 and b= 1/2 in (1) then
=> 2³(1/2)+2(1/2)³
=> (8/2)+2(1/8)
=> (8/2)+(2/8)
=> 4+(1/4)
=> (4×4+1)/4
=> (16+1)/4
=> 17/4
The value of the product is 17/4
18.
Given that s(s²-st)
=> (s×s²)-(s×st)
=> s³-s²t
The product of s(s²-st) is s³-s²t --------(1)
Put s = 2 and t = 3 in (1) then
=> 2³-2²(3)
=> 8-(4×3)
=> 8-12
=> -4
The value of the product is -4
19.
Given that -3y(xy+y²)
=> (-3y×xy)+(-3y×y²)
=> -3xy²-3y³
The product of -3y(xy+y²) is -3xy²-3y³ --------(1)
Put x = 4 and y = 5 in (1) then
=> -3(4)(5)²-3(5)³
=> -3(4)(25)-3(125)
=> -300-375
=> -675
The value of the product is -675
20.
Given that
a(b-c)+b(c-a)+c(a-b)
=> ab-ac+bc-ab+ac-ab
=> (ab-ab)+(bc-bc)+(ac-ac)
=> 0+0+0
=> 0
a(b-c)+b(c-a)+c(a-b) = 0