Math, asked by muskan0927, 1 year ago

solve 17 and 18 question

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Answered by sonukumar985
1
Q18. students were there in group=x
price of group =10x
3 more students
students recently in group=x+3
price of recently group=(x+3)8
=8x+24
price of group=price of recently group
10x=8x+24
10x-8x=24
2x=24
x=24/2=12
students were there in group=12
students recently in group=x+3=12+3=15


Q17.number of passanager=40passanagers
price of 40 passanagers=(40×1/2)rs
=20rs
number of ramananing passanagers=x
price of ramananing passanagers=(x×1.50)rs
=(1.50x)rs
total price=32rs
20+1.50x=32
(15/10)x=32-20
x=(12×10)/15=(4×2)passanagers
number of ramananing passanager=6passanagers



muskan0927: thanks
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