. Solve 18
3 + 81
2 + 121 + 60 = 0 given that one root is equal to half the
Sum of the remaining roots
Answers
Answered by
2
Answer:
please mark me as brainlist
Answered by
0
Answer:
Step-by-step explanation:
18x
3
+81x
2
+121x+60=0
One root is the half of sum of remaining roots. So roots are in AP.
Let roots be α−β,α,α+β
Sum of roots =−
18
81
=3α
α=−
2
3
So one root is x=−
2
3
Dividing 18x
3
+81x
2
+121x+60=0 by x+
2
3
we get 18x
2
+54x+40
Hence other roots are given by 18x
2
+54x+40=0
⟹9x
2
+27x+20=0
x=
2∗9
−27±
27
2
−(4∗9∗20)
=
18
−27±3
=−
3
4
,−
3
5
The roots are −
2
3
,−
3
4
,−
3
5
Similar questions