Question

solve.....................​

Answer 1

Answer:

$\large\bold{ \boxed {\color{purple}{38}}}$

Step-by-step explanation:

$\bold{let \: \: the \: \: digits \: of \: the \: \: number \: \: be \: \: x \: and \: y} \\ \\ \bold{the \: number \: is \: \: 10x + y} \\ \\ \bold{given} \\ \\ \color{red}\bold{ \boxed{x + y = 11} < 1 > } \\ \\ \bold{the \: reversed \: number \: is \: \: 10y + x} \\ \\ \bold{given} \\ \\ \color{red}\bold{ \boxed{(10x + y) + 45= (x + 10y)}} \\ \\ \bold{ = > 9y - 9x = 45} \\ \\ \bold{ = > y - x = 5} \\ \\ \color{red}\bold{ \boxed{ y - x = 5} < 2 > } \\ \\ < 1 > + < 2 > \\ \\ \bold{ = > (x + y) + (y - x) = 11 + 5} \\ \\ \bold{ = > 2y = 16} \\ \\ \bold{ = > y = 8} \\ \\ sub \: \: in \: \: < 1 > \\ \\ \bold{ = > x + 8 = 11} \\ \\ \bold{ = > x = 3} \\ \\ \color{red}\bold{ \boxed{x = 3} \: \: \: \boxed{y = 8}} \\ \\ \bold{ = > no. = 10(3) + 8 = 38} \\ \\ \large{ \bold{ \color{blue}{The \: required \: number \: is \: \boxed{ \color{orange}{38}}}}}$

$<marquee> HOPE IT HELPS$